1 条题解

  • 0
    @ 2022-12-9 0:58:45

    C :

    #include<stdio.h>
    void main()
    {
    	int i,n=0;
    	for(i = 97;i <= 122;i++){
    		printf("%c",i); 
    		n++;
    		if(n % 13 == 0){
    			printf("\n"); 
    		} 
    	} 
    	for(i = 122;i >= 97;i--){
    		printf("%c",i); 
    		n++;
    		if(n % 13 == 0){
    			printf("\n"); 
    		} 
    	} 
    
       return 0;
    }
    

    C++ :

    #include <iostream>
    using namespace std;
    int main (){
    	int i;
    	char c;
    	
    	for(i=97;i<=122;i++){
    		c=i;
    		cout<<c;
    		if(i==97+12||i==97+25){
    			cout<<endl;
    		}
    	}
    	for(i=122;i>=97;i--){
    		c=i;
    		cout<<c;
    		if(i==122-12||i==97){
    			cout<<endl;
    		}
    	}
    }
    

    Pascal :

    var
      ch:char;
    begin
      for ch:='a' to 'm' do
        write(ch);
          writeln;
             for ch:='n' to 'z' do
               write(ch);
                 writeln;
                   for ch:='z' downto 'n' do
                     write(ch);
                       writeln;
                          for ch:='m' downto 'a' do
                            write(ch);
                              writeln;
    end.
    
    
    

    Java :

    public class Main{
    	public static void main(String[] args) {
    		int n=0,m=0;
    		for(int i=1;i<=4;i++){
    			for(int j=1;j<=13;j++){
    				if(n<26){
    					System.out.print((char)(97+n));
    					n++;
    				}else{
    					m++;
    					System.out.print((char)(97+n-m));
    				}
    			}
    			System.out.println();
    		}
    	}
    }
    

    Python :

    num = 0
    numt = 0
    for i in range(97,123):
        print(chr(i),end='')
        num += 1
        if num == 13:
           print()
    print()
    for j in range(122,96,-1):
        print(chr(j),end='')
        numt += 1
        if numt == 13:
           print()
    
    • 1

    信息

    ID
    129
    时间
    1000ms
    内存
    16MiB
    难度
    10
    标签
    递交数
    15
    已通过
    0
    上传者