1 条题解
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0
C :
#include<stdio.h> int main() { int t,n,m,c1,c2,c5,k; scanf("%d",&t); while(t--) { scanf("%d%d",&n,&m); k=0; for(c5=0;5*c5<=m;c5++) for(c2=0;2*c2+5*c5<=m;c2++) { c1=m-5*c5-2*c2; if(c1+c2+c5==n) k++; } printf("%d\n",k); } return 0; }
C++ :
#include<stdio.h> int main() { int t,n,m,c1,c2,c5,k; scanf("%d",&t); while(t--) { scanf("%d%d",&n,&m); k=0; for(c5=0;5*c5<=m;c5++) for(c2=0;2*c2+5*c5<=m;c2++) { c1=m-5*c5-2*c2; if(c1+c2+c5==n) k++; } printf("%d\n",k); } return 0; }
Pascal :
program p1025; var m,n,t,i,j,k,c,s:longint; begin readln(t); for c:=1 to t do begin readln(n,m); s:=0; for i:=0 to m do for j:=0 to (m div 2) do begin k:=n-i-j; if (i+j*2+k*5=m) and (k>=0) then s:=s+1; end; writeln(s); end; end.
Java :
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); int t = in.nextInt(); while(t-->0){ int n = in.nextInt(); int m = in.nextInt(); int cou = 0; for(int i=0;i<=m;i++) for(int j=0;j<=m/2+1;j++) for(int k=0;k<=m/5+1;k++){ if(k+j>n || k+i>n || j+i>n)break; if(i+j+k==n && i+j*2+k*5==m) cou++; } System.out.println(cou); } } }
Python :
import sys def check(n,m): s=0 for i in xrange(n+1): M = m-5*i N = n-i if N <= M <=2*N: s += 1 #print i,s return s for line in sys.stdin: data = map(lambda x:int(x),line.split()) if len(data)==2: n,m=data print check(n,m)
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信息
- ID
- 6219
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者