1 条题解
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0
C :
#include<stdio.h> int main() { int t,i,n,a[20]; a[0]=1; a[1]=2; for(i=2;i<19;i++) a[i]=a[i-1]+a[i-2]; scanf("%d",&t); while(t--) { scanf("%d",&n); printf("%d\n",a[n-1]); } return 0; }
C++ :
#include<stdio.h> int main() { int t,i,n,a[20]; a[0]=1; a[1]=2; for(i=2;i<19;i++) a[i]=a[i-1]+a[i-2]; scanf("%d",&t); while(t--) { scanf("%d",&n); printf("%d\n",a[n-1]); } return 0; }
Pascal :
var i,j,k,l,n,m:longint; a:array[0..1000]of longint; begin readln(n); for i:=1 to n do begin readln(m); a[1]:=1;a[2]:=2; for j:=3 to m do a[j]:=a[j-1]+a[j-2]; writeln(a[m]); end; end.
Java :
import java.text.DecimalFormat; import java.util.ArrayList; import java.util.Collection; import java.util.Collections; import java.util.Scanner; import java.math.*; public class Main { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner in = new Scanner(System.in); String[] zong = in.nextLine().split(" "); int start = Integer.parseInt(zong[0]); for(int i=0;i<start;i++){ String[] zong1 = in.nextLine().split(" "); int c=Integer.parseInt(zong1[0]); System.out.println(jc(c)); } } public static int jc(int i) { int k = 0; if (i == 0) // 0的阶乘=1 return 1; else if (i > 0) {// 0继续递归 k = jc(i - 2) + jc(i - 1); } return k; } }
Python :
for i in range(0, int(input())): a = [1, 2] * 10 j = int(input()) for n in range(2, j): a[n] = a[n - 1] + a[n - 2] print a[j - 1]
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信息
- ID
- 6245
- 时间
- 1000ms
- 内存
- 32MiB
- 难度
- (无)
- 标签
- 递交数
- 0
- 已通过
- 0
- 上传者