1 条题解

  • 0
    @ 2024-5-10 0:45:59

    C :

    #include<stdio.h>
    
    int main()
    {
        int t,i,n,a[20];
        a[0]=1;
        a[1]=2;
        for(i=2;i<19;i++)
        	a[i]=a[i-1]+a[i-2];
        scanf("%d",&t);
        while(t--)
        {
            scanf("%d",&n);
            printf("%d\n",a[n-1]);
        }
        return 0;
    }
    

    C++ :

    #include<stdio.h>
    
    int main()
    {
        int t,i,n,a[20];
        a[0]=1;
        a[1]=2;
        for(i=2;i<19;i++)
        	a[i]=a[i-1]+a[i-2];
        scanf("%d",&t);
        while(t--)
        {
            scanf("%d",&n);
            printf("%d\n",a[n-1]);
        }
        return 0;
    }
    

    Pascal :

    var i,j,k,l,n,m:longint;
    a:array[0..1000]of longint;
    begin
    readln(n);
    for i:=1 to n do
    begin
    readln(m);
    a[1]:=1;a[2]:=2;
    for j:=3 to m do
    a[j]:=a[j-1]+a[j-2];
    writeln(a[m]);
    end;
    end. 
    

    Java :

    import java.text.DecimalFormat;
    import java.util.ArrayList;
    import java.util.Collection;
    import java.util.Collections;
    import java.util.Scanner;
    import java.math.*;
    
    public class Main {
    
    	/**
    	 * @param args
    	 */
    	public static void main(String[] args) {
    		// TODO Auto-generated method stub
    		Scanner in = new Scanner(System.in);
    		String[] zong = in.nextLine().split(" ");
    		int start = Integer.parseInt(zong[0]);
    		 for(int i=0;i<start;i++){
    		 String[] zong1 = in.nextLine().split(" ");
    		int c=Integer.parseInt(zong1[0]);
    		System.out.println(jc(c));
    		 }
    
    	}
    
    	public static int jc(int i) {
    		int k = 0;
    		if (i == 0) // 0的阶乘=1
    			return 1;
    		else if (i > 0) {// 0继续递归
    			k = jc(i - 2) + jc(i - 1);
    		}
    		return k;
    	}
    }
    

    Python :

    for i in range(0, int(input())):
        a = [1, 2] * 10
        j = int(input())
        for n in range(2, j):
            a[n] = a[n - 1] + a[n - 2]
        print a[j - 1]
    
    • 1

    信息

    ID
    6245
    时间
    1000ms
    内存
    32MiB
    难度
    (无)
    标签
    递交数
    0
    已通过
    0
    上传者